A man can row upstream 36 text{ km} in 6 text | vedclass

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(D) Let the speed of the man in still water be $x = 8 	ext{ km/hr}$ and the speed of the current be $y 	ext{ km/hr}$.The speed upstream is given by

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$100$

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(D) Let the speed of the man in still water be $x = 8 	ext{ km/hr}$ and the speed of the current be $y 	ext{ km/hr}$.The speed upstream is given by $(x - y)$.Given that the man rows $36 	ext{ km}$ upstream in $6 	ext{ hours}$,we have:$\frac{36}{x - y} = 6$$\frac{36}{8 - y} = 6$$36 = 6(8 - y)$$36 = 48 - 6y$$6y = 48 - 36$$6y = 12$$y = 2 	ext{ km/hr}$.The speed downstream is given by $(x + y) = 8 + 2 = 10 	ext{ km/hr}$.To find the distance covered downstream in $10 	ext{ hours}$:$	ext{Distance} = 	ext{Speed} 	imes 	ext{Time}$$	ext{Distance} = 10 	ext{ km/hr} 	imes 10 	ext{ hours} = 100 	ext{ km}$.

$A$ man can row upstream $36 \text{ km}$ in $6 \text{ hours}$. If the speed of a man in still water is $8 \text{ km/hr}$,find how much distance he can cover downstream in $10 \text{ hours}$? (in $\text{km}$)

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