A man borrows ₹ 3825 to be paid back with com | vedclass

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Question

Let each instalment be ₹ $x$.

$	herefore \quad \frac{x}{\left(1+\frac{4}{100}ight)^{2}}+\frac{x}{\left(1+\frac{4}{100}ight)}=3825$

i.e. $\q

Vedclass · Accepted Answer

$2028$

Vedclass · Answer

Let each instalment be ₹ $x$.

$	herefore \quad \frac{x}{\left(1+\frac{4}{100}ight)^{2}}+\frac{x}{\left(1+\frac{4}{100}ight)}=3825$

i.e. $\quad \frac{x}{\left(\frac{26}{25}ight)^{2}}+\frac{x}{\left(\frac{26}{25}ight)}=3825$

$x+x 	imes \frac{26}{25}=3825 	imes\left(\frac{26}{25}ight)^{2}$

i.e. $x 	imes \frac{51}{25}=3825 	imes \frac{(26)^{2}}{(25)^{2}}$

$\begin{aligned}x &=3825 	imes \frac{(26)^{2}}{(25)^{2}} 	imes \frac{25}{51} \&=\frac{153 	imes(26)^{2}}{51}=3 	imes(26)^{2}=₹ 2028\end{aligned}$

A man borrows ₹ $3825$ to be paid back with compound interest at the rate of $4 \%$ per annum by the end of $2$ years into equal yearly instalments. How much will be each instalment (In ₹) ?

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