A man balances himself in a horizontal positi | vedclass

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(B) Let the normal force exerted by the man on each wall be $N$. Since the man is in equilibrium,the total horizontal force must be zero,so the walls

Vedclass · Accepted Answer

He exerts only horizontal forces on the walls

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(B) Let the normal force exerted by the man on each wall be $N$. Since the man is in equilibrium,the total horizontal force must be zero,so the walls exert an equal normal force $N$ on the man.Let the friction force exerted by each wall on the man be $f$. For vertical equilibrium,$2f = mg$,so $f = mg/2$. Thus,the friction forces are equal.The total force exerted by each wall on the man is the vector sum of the normal force $N$ and the friction force $f$,which is $\vec{R} = \vec{N} + \vec{f}$. Since $\vec{f}$ is vertical and $\vec{N}$ is horizontal,the resultant force $\vec{R}$ is not horizontal.Option $(B)$ states that he exerts only horizontal forces on the walls. However,to maintain equilibrium,the man must also exert a downward frictional force on the walls to balance the upward frictional force exerted by the walls on him. Therefore,he exerts both horizontal and vertical forces on the walls. Thus,$(B)$ is incorrect.

$A$ man balances himself in a horizontal position by pushing his hands and feet against two parallel walls. His centre of mass lies midway between the walls. The coefficients of friction at the walls are equal. Which of the following is not correct?

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