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(C) The genotype of the male is $AaBbX^hY$. Since genes $A$ and $B$ are autosomal and heterozygous,they will segregate independently during meiosis. T

Vedclass · Accepted Answer

$\frac{1}{8}$

Vedclass · Answer

(C) The genotype of the male is $AaBbX^hY$. Since genes $A$ and $B$ are autosomal and heterozygous,they will segregate independently during meiosis. The gene $h$ is $X$-linked. The possible gametes formed by this male are determined by the combination of alleles: $1$. Autosomal alleles: $A, a, B, b$ can form four combinations: $AB, Ab, aB, ab$ (each with a probability of $\frac{1}{4}$). $2$. Sex chromosomes: $X^h$ and $Y$ (each with a probability of $\frac{1}{2}$). To obtain a sperm with the genotype $abh$,the combination must be $ab$ from the autosomes and $h$ from the sex chromosome (specifically $X^h$). Probability of $ab = \frac{1}{2} 	imes \frac{1}{2} = \frac{1}{4}$. Probability of $X^h = \frac{1}{2}$. Therefore,the total probability of producing an $abh$ sperm is $\frac{1}{4} 	imes \frac{1}{2} = \frac{1}{8}$.

$A$ male human is heterozygous for autosomal genes $A$ and $B$ and is also hemizygous for the hemophilic gene $h$. What proportion of his sperms will be $abh$?

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