A long straight wire carries a current of 35, | vedclass

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(A) The current flowing through the long straight wire is $I = 35\, A$.The distance of the point from the wire is $r = 20\, cm = 0.2\, m$.The magnetic

Vedclass · Accepted Answer

$3.5 	imes 10^{-5}\, T$

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(A) The current flowing through the long straight wire is $I = 35\, A$.The distance of the point from the wire is $r = 20\, cm = 0.2\, m$.The magnetic field $B$ at a distance $r$ from a long straight current-carrying wire is given by the formula:$B = \frac{\mu_0 I}{2 \pi r}$Substituting the values:$B = \frac{(4 \pi 	imes 10^{-7}\, T \cdot m/A) 	imes 35\, A}{2 \pi 	imes 0.2\, m}$$B = \frac{2 	imes 10^{-7} 	imes 35}{0.2}\, T$$B = \frac{70 	imes 10^{-7}}{0.2}\, T$$B = 350 	imes 10^{-7}\, T = 3.5 	imes 10^{-5}\, T$.

$A$ long straight wire carries a current of $35\, A$. What is the magnitude of the magnetic field $B$ at a point $20\, cm$ from the wire?

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