A light wave is incident normally on a slit o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For single slit diffraction,the condition for the $n^{th}$ dark fringe is given by $d \sin 	heta = n \lambda$,where $d$ is the slit width,$	heta

Vedclass · Accepted Answer

$6000$

Vedclass · Answer

(A) For single slit diffraction,the condition for the $n^{th}$ dark fringe is given by $d \sin 	heta = n \lambda$,where $d$ is the slit width,$	heta$ is the angular position,and $n$ is the order of the fringe.Given: Slit width $d = 24 	imes 10^{-5} \ cm = 24 	imes 10^{-7} \ m$.Order of fringe $n = 2$.Angular position $	heta = 30^{\circ}$.Substituting the values into the formula: $24 	imes 10^{-7} 	imes \sin(30^{\circ}) = 2 	imes \lambda$.Since $\sin(30^{\circ}) = 0.5$,we have $24 	imes 10^{-7} 	imes 0.5 = 2 \lambda$.$12 	imes 10^{-7} = 2 \lambda$.$\lambda = 6 	imes 10^{-7} \ m$.Converting to $\mathring{A}$: $\lambda = 6 	imes 10^{-7} 	imes 10^{10} \ \mathring{A} = 6000 \ \mathring{A}$.

$A$ light wave is incident normally on a slit of width $24 \times 10^{-5} \ cm$. The angular position of the second dark fringe from the central maxima is $30^{\circ}$. What is the wavelength of light in $\mathring{A}$?

Similar Questions

In a reaction of $C_6H_5Y$,the major product $(> 60\%)$ is $m$-isomer,so the group $Y$ is:

If $p$ and $q$ are the perpendicular distances from the origin to the straight lines $x \sec \theta - y \operatorname{cosec} \theta = a$ and $x \cos \theta + y \sin \theta = a \cos 2 \theta$,then

Heating phthalic anhydride and concentrated sulfuric acid with which of the following yields phenolphthalein?

The element californium belongs to the family

$A$ number $n$ is chosen at random from $\{1, 2, 3, 4, \ldots, 1000\}$. The probability that $n$ is a number that leaves remainder $1$ when divided by $7$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module