A light rod acted upon by three forces is in | vedclass

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(B) For a body to be in equilibrium under the action of three forces, two conditions must be satisfied:$1$. The net force acting on the body must be z

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(B) For a body to be in equilibrium under the action of three forces, two conditions must be satisfied:$1$. The net force acting on the body must be zero $(\sum \vec{F} = 0)$. This implies that the three force vectors must form a closed triangle when placed head-to-tail.$2$. The net torque about any point must be zero $(\sum \vec{	au} = 0)$. This implies that the lines of action of the three forces must be concurrent (i.e., they must intersect at a single point) or they must be parallel.In the given diagrams, we look for the configuration where the lines of action of the three forces $P$, $Q$, and $R$ intersect at a single point. In diagram $B$, the lines of action of forces $P$, $Q$, and $R$ can be extended to meet at a common point, satisfying the condition for zero net torque. Thus, it represents a possible equilibrium configuration.

$A$ light rod acted upon by three forces is in equilibrium. Which of the following diagrams shows the possible position and direction of the forces?

Similar Questions

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