A light ray is incident upon a prism in minim | vedclass

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(C) For a thin prism,the angle of deviation $\delta$ is given by $\delta = (n - 1)A$,where $n$ is the refractive index and $A$ is the prism angle.Init

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Suffer a deviation of $17^o$

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(C) For a thin prism,the angle of deviation $\delta$ is given by $\delta = (n - 1)A$,where $n$ is the refractive index and $A$ is the prism angle.Initially,the deviation is $\delta = 34^o = (n - 1)A$.When the shaded half is removed,the effective prism angle becomes $A' = A/2$.The new deviation $\delta'$ will be $\delta' = (n - 1)A' = (n - 1)(A/2)$.Substituting the initial value: $\delta' = \frac{1}{2} 	imes (n - 1)A = \frac{1}{2} 	imes 34^o = 17^o$.Thus,the ray will suffer a deviation of $17^o$.

$A$ light ray is incident upon a prism in minimum deviation position and suffers a deviation of $34^o$. If the shaded half of the prism is removed,the ray will

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