$A$ light bulb,a capacitor,and a battery are connected in a series circuit as shown in the figure,with switch $S$ initially open. When the switch $S$ is closed,which one of the following is true?

  • A
    The bulb will light up for an instant when the capacitor starts charging.
  • B
    The bulb will light up when the capacitor is fully charged.
  • C
    The bulb will not light up at all.
  • D
    The bulb will light up and go off at regular intervals.

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In the circuit shown,the switch is shifted from position $1 \rightarrow 2$ at $t = 0$. The switch was initially in position $1$ for a long time. The graph between the charge on capacitor $C$ and time $t$ is:

In the circuit given,the charge on the capacitor is

After the switch shown in Figure $A$ is closed,there is a current $i$ through the resistance $R$. Figure $B$ indicates current variation curves $a, b, c,$ and $d$ for four sets of values of $R$ and capacitance $C$:
$(i)$ $R_0$ and $C_0$
$(ii)$ $2R_0$ and $C_0$
$(iii)$ $R_0$ and $2C_0$
$(iv)$ $2R_0$ and $2C_0$
Which set goes with which curve?

Find the current from the battery at $(i)$ $t \rightarrow 0$ (initial) and $(ii)$ $t \rightarrow \infty$ (after a long time) when the switch is closed at $t = 0$.

As shown in the figure,if a capacitor of capacitance $C$ is charged by connecting it with a resistance $R$ and a battery of $EMF$ $V$,then the total energy supplied by the battery is:

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