$A$ lens of refractive index $n$ is placed in a liquid of refractive index $n'$. If the focal length of the lens in air is $f$,what will be its focal length in the liquid?

  • A
    $ - \frac{fn'(n - 1)}{n' - n}$
  • B
    $ - \frac{f(n' - n)}{n'(n - 1)}$
  • C
    $ - \frac{n'(n - 1)}{f(n' - n)}$
  • D
    $\frac{fn'n}{n - n'}$

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