(N/A) $(i)$ Both vehicles experience the same magnitude of force. According to Newton's third law of motion,for every action,there is an equal and opposite reaction. Thus,the force exerted by the truck on the car is equal to the force exerted by the car on the truck.
$(ii)$ The truck experiences a greater change in momentum. Momentum is defined as $p = mv$. Since the truck has a much larger mass $(M)$ compared to the car $(m)$,and both come to a halt (final velocity $= 0$),the change in momentum $\Delta p = |0 - mv| = mv$ is greater for the truck.
$(iii)$ The car experiences greater acceleration. According to Newton's second law,$F = ma$,which implies $a = F/m$. Since the force $(F)$ is the same for both,the vehicle with the smaller mass $(m)$ will experience a larger acceleration $(a)$.