A is 50% as efficient as B. C does half of th | vedclass

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(B) 's efficiency $= \frac{1}{20}$ work/day.Since $C$ does half the work of $(A+B)$ in the same time,the efficiency of $(A+B) = 2 	imes C$'s efficien

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$6 \frac{2}{3}$

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(B) 's efficiency $= \frac{1}{20}$ work/day.Since $C$ does half the work of $(A+B)$ in the same time,the efficiency of $(A+B) = 2 	imes C$'s efficiency = $2 	imes \frac{1}{20} = \frac{1}{10}$ work/day.Given $A$ is $50\%$ as efficient as $B$,$A = 0.5B$,or $B = 2A$.Substituting $B$ in $(A+B)$ efficiency: $A + 2A = \frac{1}{10} \implies 3A = \frac{1}{10} \implies A = \frac{1}{30}$ work/day.$B$'s efficiency $= 2 	imes \frac{1}{30} = \frac{1}{15}$ work/day.Total efficiency of $(A+B+C) = \frac{1}{30} + \frac{1}{15} + \frac{1}{20} = \frac{2 + 4 + 3}{60} = \frac{9}{60} = \frac{3}{20}$ work/day.Time taken by $(A+B+C)$ together $= \frac{1}{3/20} = \frac{20}{3} = 6 \frac{2}{3} 	ext{ days}$.

$A$ is $50\%$ as efficient as $B$. $C$ does half of the work done by $A$ and $B$ together in the same time. If $C$ alone does the work in $20 \text{ days}$,then $A, B$,and $C$ together can do the work in (in $\text{days}$):

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