A hydrocarbon C_5H_{12} does not react with c | vedclass

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(D) The hydrocarbon $C_5H_{12}$ is an alkane. Alkanes do not react with chlorine in the dark but undergo free-radical substitution in the presence of

Vedclass · Accepted Answer

None of these

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(D) The hydrocarbon $C_5H_{12}$ is an alkane. Alkanes do not react with chlorine in the dark but undergo free-radical substitution in the presence of sunlight.$n$-pentane $(CH_3-CH_2-CH_2-CH_2-CH_3)$ has three types of equivalent hydrogens,yielding three monochloro isomers.Isopentane $(CH_3-CH(CH_3)-CH_2-CH_3)$ has four types of equivalent hydrogens,yielding four monochloro isomers.Neopentane $(C(CH_3)_4)$ has only one type of equivalent hydrogen,yielding only one monochloro isomer.Since the question asks for a hydrocarbon that gives six monochloro compounds,and none of the standard isomers of $C_5H_{12}$ produce six,there might be a misunderstanding in the question's premise or it refers to a different hydrocarbon. However,based on the options provided,none are correct.

$A$ hydrocarbon $C_5H_{12}$ does not react with chlorine in the dark but gives six monochloro compounds in bright sunlight. The hydrocarbon is:

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