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(D) Colour blindness is an $X$-linked recessive disorder.Since the husband and wife have normal vision,their genotypes are:Husband: $X^CY$ (where $C$

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(D) Colour blindness is an $X$-linked recessive disorder.Since the husband and wife have normal vision,their genotypes are:Husband: $X^CY$ (where $C$ is normal vision,$c$ is colour blind).Wife: $X^CX^c$ (she is a carrier because her father was colour blind,$X^cY$).The cross is: $X^CY 	imes X^CX^c$.The possible genotypes of their children are: $X^CX^C$ (normal daughter),$X^CX^c$ (carrier daughter),$X^CY$ (normal son),$X^cY$ (colour blind son).For a daughter to be colour blind,she must inherit the $X^c$ allele from both parents $(X^cX^c)$.Since the father has normal vision $(X^CY)$,he cannot pass the $X^c$ allele to his daughter.Therefore,the probability of their daughter being colour blind is $0\%$.

$A$ husband and wife have normal vision,but the fathers of both of them were colour blind. What is the probability of their first daughter being colour blind (in $\%$)?

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