A horizontal metallic rod of mass $'m'$ and length $'l'$ is supported by two vertical identical springs of spring of spring constant $'K'$ each and natural length $l_0.$  A current $'i'$ is flowing in the rod in the direction shown. If the rod is in equilibrium then the length of each spring in this state is :-

Assertion $(A):$ A wire bent into an irregular shape with the points $P$ and $Q$ fixed. If a current $I$ passed through the wire, then the area enclosed by the irregular portion of the wire increases.

Reason $(R):$ Opposite currents carrying wires repel each other.

A metal ring of radius $r = 0.5 \,\,m $ with its plane normal to a uniform magnetic field $B$ of induction $0.2 T$ carries a current $I = 100\,\, A$. The tension in newtons developed in the ring is:

Wires $1$ and $2$ carrying currents ${i_1}$ and ${i_2}$respectively are inclined at an angle $\theta $ to each other. What is the force on a small element $dl$ of wire $2$ at a distance of $r$ from wire $1$ (as shown in figure) due to the magnetic field of wire $1$

If a wire of length $1\, meter$ placed in uniform magnetic field $1.5\, Tesla$ at angle ${30^o}$ with magnetic field. The current in a wire $10\, amp$. Then force on a wire will be.......$N$

Two long current carrying thin wires, both with current $I$, are held by insulating threads oflength $L$ and are in equilibrium as shown in the figure, with threads making an angle '$\theta$' with the vertical. If wires have mass $\lambda$ per unit length then the value of $l$ is 
($g =$ gravitational acceleration)