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(B) Given: Inner radius $(r)$ = $4 \, cm$,Thickness $(t)$ = $0.2 \, cm$. The outer radius $(R)$ = $r + t = 4 + 0.2 = 4.2 \, cm$. The formula for the c

Vedclass · Accepted Answer

$110.88$

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(B) Given: Inner radius $(r)$ = $4 \, cm$,Thickness $(t)$ = $0.2 \, cm$. The outer radius $(R)$ = $r + t = 4 + 0.2 = 4.2 \, cm$. The formula for the curved surface area of a hemisphere is $2 \pi R^2$. Outer curved surface area = $2 	imes \frac{22}{7} 	imes (4.2)^2$. $= 2 	imes \frac{22}{7} 	imes 4.2 	imes 4.2$. $= 2 	imes 22 	imes 0.6 	imes 4.2$. $= 44 	imes 2.52 = 110.88 \, cm^2$.

$A$ hemispherical metallic bowl is made of steel,$0.2 \, cm$ thick. The inner radius of the bowl is $4 \, cm$. Find the outer curved surface area of the bowl (in $cm^2$).

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