A hemispherical bowl of radius r is set rotat | vedclass

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Question

(b)

$Hint:$ Use the Newton's second law to balances the forces in $x$ and $y$ directions.

$Step\,1:$ Draw the free body diagram of the syste

Vedclass · Accepted Answer

$\omega=\sqrt{ g / rcos 	heta}$

Vedclass · Answer

(b)

$Hint:$ Use the Newton's second law to balances the forces in $x$ and $y$ directions.

$Step\,1:$ Draw the free body diagram of the system.

Step 2:Balance the forces in horizontal and vertical direction. Balancing forces along vertical direction.

$N \cos 	heta=m g$

Balancing forces along horizontal direction.

$\Sigma F _{ nes }=m\left( a _2ight)$

$N \sin 	heta=m\left(\omega^2 right)$

Here, $r=r \sin 	heta$.

$N$ is the normal reaction, $m$ is the mass of the block and $g$ is the acceleration due to gravity.

Step $3$: Solve the equations.

Dividing equation $1$ and $2$ and using equation $3$ , we get:

$\omega=\sqrt{\frac{g}{r \cos 	heta}}$

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