$A$ heavy rope is suspended from a rigid support. $A$ transverse wave pulse is set up at the lower end,then

The fundamental frequency of vibration of a string stretched between two rigid supports is $50\,Hz$. The mass of the string is $18\,g$ and its linear mass density is $20\,g/m$. The speed of the transverse waves produced in the string is $..........\,m/s$.

$A$ transverse wave propagating on a string can be described by the equation $y = 2 \sin (10x + 300t)$,where $x$ and $y$ are in meters and $t$ is in seconds. If the vibrating string has a linear mass density of $0.6 \times 10^{-3} \, g/cm$,then the tension in the string is .............. $N$.

$A$ string of length $L$ is stretched by $\frac{L}{20}$ and the speed of transverse waves along it is $v$. The speed of the wave when it is stretched by $\frac{L}{10}$ will be (assume that Hooke's law is applicable).

$A$ string has a mass per unit length of $10^{-6} \,kg/cm$. The equation of a simple harmonic wave produced in it is $Y=0.2 \sin(2x+80t) \,m$. The tension in the string is: (in $N$)

$A$ heavy uniform rope is suspended vertically from a ceiling and is in equilibrium. $A$ pulse is generated at the bottom end of the rope as shown. As the pulse travels up the rope,its acceleration at any instant is ($g$ is acceleration due to gravity).