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(B) The excess pressure inside a soap bubble of radius $r$ is given by $\Delta P = \frac{4T}{r}$,where $T$ is the surface tension.Let $P_0$ be the atm

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air from end $1$ flows towards end $2$. Volume of the soap bubble at end $1$ decreases.

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(B) The excess pressure inside a soap bubble of radius $r$ is given by $\Delta P = \frac{4T}{r}$,where $T$ is the surface tension.Let $P_0$ be the atmospheric pressure.The pressure inside the bubble at end $1$ (radius $r$) is $P_1 = P_0 + \frac{4T}{r}$.The pressure inside the bubble at end $2$ (radius $R$) is $P_2 = P_0 + \frac{4T}{R}$.Given that $R > r$,it follows that $\frac{4T}{R} Therefore,$P_2 Since air flows from a region of higher pressure to a region of lower pressure,air will flow from end $1$ to end $2$.As air leaves the bubble at end $1$,its volume decreases.

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