A glass flask is filled up to a mark with 50, | vedclass

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Question

(C) The apparent expansion of mercury relative to the glass flask is given by the formula: $\Delta V = V_0 (\gamma_{real} - \gamma_{glass}) \Delta T$.

Vedclass · Accepted Answer

$0.15$

Vedclass · Answer

(C) The apparent expansion of mercury relative to the glass flask is given by the formula: $\Delta V = V_0 (\gamma_{real} - \gamma_{glass}) \Delta T$. Since the coefficient of volume expansion of glass $\gamma_{glass} = 3\alpha_{glass}$,we have $\gamma_{glass} = 3 	imes 9 	imes 10^{-6} {^{\circ}C}^{-1} = 27 	imes 10^{-6} {^{\circ}C}^{-1}$. The change in temperature is $\Delta T = 38^{\circ}C - 18^{\circ}C = 20^{\circ}C$. Substituting the values: $\Delta V = 50 	imes (180 	imes 10^{-6} - 27 	imes 10^{-6}) 	imes 20$. $\Delta V = 50 	imes (153 	imes 10^{-6}) 	imes 20 = 1000 	imes 153 	imes 10^{-6} = 0.153\, cc$. Rounding to two decimal places,the amount of mercury above the mark is $0.15\, cc$.

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