A gas at 27^{circ}C has a volume V and pressu | vedclass

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(C) Using the ideal gas equation $PV = nRT$,for a fixed amount of gas,we have $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given initial temperature $T

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$1527$

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(C) Using the ideal gas equation $PV = nRT$,for a fixed amount of gas,we have $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$.Given initial temperature $T_1 = 27 + 273 = 300 \ K$.Initial pressure is $P_1 = P$ and initial volume is $V_1 = V$.Final pressure $P_2 = 2P$ and final volume $V_2 = 3V$.Substituting these values into the equation: $\frac{P \cdot V}{300} = \frac{(2P) \cdot (3V)}{T_2}$.$\frac{1}{300} = \frac{6}{T_2}$.$T_2 = 6 	imes 300 = 1800 \ K$.To convert to Celsius: $T_2(^{\circ}C) = 1800 - 273 = 1527^{\circ}C$.

$A$ gas at $27^{\circ}C$ has a volume $V$ and pressure $P$. On heating,its pressure is doubled and volume becomes three times. The resulting temperature of the gas will be ...... $^{\circ}C$.

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