A garden is 24, m long and 14, m wide. There | vedclass

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(C) Area of the garden $= 24\, m 	imes 14\, m = 336\, m^2$.The path is $1\, m$ wide outside the garden,so the new length $= 24 + 1 + 1 = 26\, m$ and

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$2000$

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(C) Area of the garden $= 24\, m 	imes 14\, m = 336\, m^2$.The path is $1\, m$ wide outside the garden,so the new length $= 24 + 1 + 1 = 26\, m$ and the new width $= 14 + 1 + 1 = 16\, m$.Area of the (garden $+$ path) $= 26\, m 	imes 16\, m = 416\, m^2$.Area of the path $= 416\, m^2 - 336\, m^2 = 80\, m^2$.Area of $1$ tile $= 20\, cm 	imes 20\, cm = 400\, cm^2$.Since $1\, m^2 = 10000\, cm^2$,the area of $1$ tile in $m^2 = \frac{400}{10000} = 0.04\, m^2$.Number of tiles required $= \frac{	ext{Area of the path}}{	ext{Area of 1 tile}} = \frac{80}{0.04} = 2000$.

$A$ garden is $24\, m$ long and $14\, m$ wide. There is a path $1\, m$ wide outside the garden along its sides. If the path is to be constructed with square marble tiles of $20\, cm \times 20\, cm$,then find the number of tiles required to cover the path.

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