$A$ galvanometer has $36\,\Omega$ resistance. If a $4\,\Omega$ shunt is added to this,the fraction of current that passes through the shunt is

  • A
    $\frac{1}{4}$
  • B
    $\frac{1}{9}$
  • C
    $\frac{1}{10}$
  • D
    $\frac{9}{10}$

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