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(C) The resistance of the galvanometer $G$ is given by $G = \frac{V_g}{I_g} = \frac{0.15 \ V}{50 	imes 10^{-3} \ A} = 3 \ \Omega$.To convert the galv

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$0.0015$

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(C) The resistance of the galvanometer $G$ is given by $G = \frac{V_g}{I_g} = \frac{0.15 \ V}{50 	imes 10^{-3} \ A} = 3 \ \Omega$.To convert the galvanometer into an ammeter of range $I = 100 \ A$,we connect a shunt resistance $S$ in parallel.The formula for shunt resistance is $S = \frac{I_g G}{I - I_g}$.Substituting the values: $S = \frac{50 	imes 10^{-3} 	imes 3}{100 - 50 	imes 10^{-3}}$.$S = \frac{0.15}{100 - 0.05} = \frac{0.15}{99.95} \approx 0.0015 \ \Omega$.

$A$ galvanometer gives a full-scale reading of $50 \ mA$,when a potential difference across its terminals is $0.15 \ V$. It can be used as an ammeter of range $0 - 100 \ A$ by connecting a shunt resistance of: (in $Omega$)

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