A fraction which bears the same ratio to frac | vedclass

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Question

(A) Let the required fraction be $x$.According to the problem,the ratio of $x$ to $\frac{1}{27}$ is equal to the ratio of $\frac{3}{11}$ to $\frac{5}{

Vedclass · Accepted Answer

$\frac{1}{55}$

Vedclass · Answer

(A) Let the required fraction be $x$.According to the problem,the ratio of $x$ to $\frac{1}{27}$ is equal to the ratio of $\frac{3}{11}$ to $\frac{5}{9}$.This can be written as: $\frac{x}{1/27} = \frac{3/11}{5/9}$.Simplifying the equation: $x 	imes 27 = \frac{3}{11} 	imes \frac{9}{5}$.$x 	imes 27 = \frac{27}{55}$.Dividing both sides by $27$,we get: $x = \frac{27}{55} 	imes \frac{1}{27} = \frac{1}{55}$.Therefore,the required fraction is $\frac{1}{55}$.

$A$ fraction which bears the same ratio to $\frac{1}{27}$ that $\frac{3}{11}$ does to $\frac{5}{9}$ is equal to

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