A force of $20\,dyne$ applied to the end of spring increase its length of $1\, mm$, then force constant will be what ?
A force of $20\,dyne$ applied to the end of spring increase its length of $1\, mm$, then force constant will be what ?
$k=\frac{\mathrm{F}}{\Delta l}=\frac{20}{0.1}=200 \mathrm{dyne} / \mathrm{cm} .$
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