A force of (3hat i + 4hat j), N acts on a bod | vedclass

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Question

(D) Work done is defined as the dot product of the force vector $\vec F$ and the displacement vector $\vec d$.Given,$\vec F = (3\hat i + 4\hat j)\, N$

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(D) Work done is defined as the dot product of the force vector $\vec F$ and the displacement vector $\vec d$.Given,$\vec F = (3\hat i + 4\hat j)\, N$ and $\vec d = (3\hat i + 4\hat j)\, m$.The formula for work done is $W = \vec F \cdot \vec d$.Substituting the values,we get $W = (3\hat i + 4\hat j) \cdot (3\hat i + 4\hat j)$.Using the dot product property $\hat i \cdot \hat i = 1$,$\hat j \cdot \hat j = 1$,and $\hat i \cdot \hat j = 0$,we calculate:$W = (3 	imes 3) + (4 	imes 4) = 9 + 16 = 25\, J$.

$A$ force of $(3\hat i + 4\hat j)\, N$ acts on a body and displaces it by $(3\hat i + 4\hat j)\, m$. The work done by the force is ............. $J$.

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