$A$ force $\vec F = (5\hat i + 3\hat j + 2\hat k) \, N$ is applied to a particle which displaces it from its origin to the point $\vec r = (2\hat i - \hat j) \, m$. The work done on the particle in joules is

$A$ force $\vec F = 5\hat i + 6\hat j - 4\hat k$ acting on a body produces a displacement $\vec s = 6\hat i + 5\hat k$. The work done by the force is $......$ units.

$A$ man of mass $50 \ kg$ carrying a load of $10 \ kg$ reaches the top of a building in $4 \ minutes$. The work done by the man is $6 \times 10^4 \ J$. If he reaches the top in $2 \ minutes$,the work done by the man will be:

At time $t=0$,a particle starts moving along the $x$-axis. If its kinetic energy increases uniformly with time $t$,the net force acting on it must be proportional to

How much work does a pulling force of $40 \,N$ do on a $20 \,kg$ box in pulling it $8 \,m$ across the floor at a constant speed? The pulling force is directed at $60^\circ$ above the horizontal.

$A$ particle moves from position $\vec{r_1} = 3\,\hat{i} + 2\,\hat{j} - 6\,\hat{k}$ to position $\vec{r_2} = 14\,\hat{i} + 13\,\hat{j} + 9\,\hat{k}$ under the influence of a force $\vec{F} = 4\,\hat{i} + \hat{j} + 3\,\hat{k}$. Find the work done in $J$.