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(D) The average kinetic energy per molecule of an ideal gas is given by the formula $K.E. = \frac{3}{2} k T$,where $k$ is the Boltzmann constant and $

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$1: 1$

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(D) The average kinetic energy per molecule of an ideal gas is given by the formula $K.E. = \frac{3}{2} k T$,where $k$ is the Boltzmann constant and $T$ is the absolute temperature.Since the mixture is in thermal equilibrium,both argon and oxygen are at the same temperature $T = 27^{\circ} C = 300 \ K$.The average kinetic energy per molecule depends only on the temperature $T$ and not on the mass or the nature of the gas.Therefore,the ratio of the average kinetic energy per molecule for argon and oxygen is $\frac{K_{Ar}}{K_{O_2}} = \frac{\frac{3}{2} k T}{\frac{3}{2} k T} = 1: 1$.

$A$ flask contains argon and oxygen in the ratio of $3: 2$ in mass and the mixture is kept at $27^{\circ} C$. The ratio of their average kinetic energy per molecule respectively will be ...........

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