A fire hydrant delivers water of density $\rho$ at a volume rate $L$. The water travels vertically upward through the hydrant and then does $90^o $ turn to emerge horizontally at speed $V$. The pipe and nozzle have uniform crosssection throughout. The force exerted by the water on the corner of the hydrant is
$\rho$ $V_L$
zero
$2\rho$ $ V_L$
$\sqrt {\rm{2}} \rho VL$
Water is filled up to a height $h$ in a beaker of radius $R$ as shown in the figure. The density of water is $\rho$, the surface tension of water is $T$ and the atmospheric pressure is $P_0$. Consider a vertical section $A B C D$ of the water column through a diameter of the beaker. The force on water on one side of this section by water on the other side of this section has magnitude
Two immiscible liquids $A$ and $B$ are kept in an U-tube. If the density of liquid $A$ is smaller than the density of liquid $B$, then the equilibrium situation is
In a $U-$ tube experiment, a column $AB$ of water is balanced by a column $‘CD’$ of oil, as shown in the figure. Then the relative density of oil is
When an air bubble rises from the bottom of a deep lake to a point just below the water surface, the pressure of air inside the bubble
If the atmospheric pressure is $P_a$, then the pressure $P$ at depth $h$ below the surface of liquid of density $\rho $ open to the atmosphere is