A few electric field lines for a system of tw | vedclass

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(A) $1$. The number of electric field lines originating from a charge is proportional to the magnitude of the charge. By counting the lines,we see tha

Vedclass · Accepted Answer

$(A, D)$

Vedclass · Answer

(A) $1$. The number of electric field lines originating from a charge is proportional to the magnitude of the charge. By counting the lines,we see that more lines originate from $Q_1$ than terminate at $Q_2$,which implies $|Q_1| > |Q_2|$. Thus,statement $(A)$ is correct.$2$. Since the charges have opposite signs (lines originate from $Q_1$ and terminate at $Q_2$),the neutral point (where the electric field is zero) must lie on the line joining the charges,outside the region between them,and closer to the charge with the smaller magnitude.$3$. Since $|Q_1| > |Q_2|$,the neutral point must be closer to $Q_2$. Therefore,the electric field is zero at a finite distance to the right of $Q_2$. Thus,statement $(D)$ is correct.$4$. Combining these,the correct option is $(A, D)$.

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