A father with 8 children takes them 3 at a ti | vedclass

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Question

(C) The number of times the father can visit the garden is equivalent to the number of ways to choose a group of $3$ children out of $8$ available chi

Vedclass · Accepted Answer

$56$

Vedclass · Answer

(C) The number of times the father can visit the garden is equivalent to the number of ways to choose a group of $3$ children out of $8$ available children.Since the order of children in the group does not matter,we use the combination formula $^nC_r = \frac{n!}{r!(n-r)!}$.Here,$n = 8$ and $r = 3$.Therefore,the required number of ways is $^8C_3 = \frac{8 	imes 7 	imes 6}{3 	imes 2 	imes 1} = 56$.Thus,the father will go to the garden $56$ times.

$A$ father with $8$ children takes them $3$ at a time to the Zoological gardens,as often as he can without taking the same $3$ children together more than once. The number of times he will go to the garden is

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