$A$ drinking glass is in the shape of a frustum of a cone of height $14 \, cm$. The diameters of its two circular ends are $4 \, cm$ and $2 \, cm$. Find the capacity of the glass. [Use $\pi = \frac{22}{7}$]

(N/A) Radius $(r_1)$ of the upper base of the glass $= \frac{4}{2} = 2 \, cm$.
Radius $(r_2)$ of the lower base of the glass $= \frac{2}{2} = 1 \, cm$.
Height $(h)$ of the glass $= 14 \, cm$.
Capacity of the glass $=$ Volume of the frustum of a cone
$= \frac{1}{3} \pi h (r_1^2 + r_2^2 + r_1 r_2)$
$= \frac{1}{3} \times \frac{22}{7} \times 14 \times (2^2 + 1^2 + 2 \times 1)$
$= \frac{1}{3} \times 22 \times 2 \times (4 + 1 + 2)$
$= \frac{44}{3} \times 7 = \frac{308}{3} \, cm^3 = 102 \frac{2}{3} \, cm^3$.
Therefore,the capacity of the glass is $102 \frac{2}{3} \, cm^3$.