$A$ double slit experiment is performed by using light of wavelength $6000 \, Å$. If the distance of the screen is $1 \, m$ and the slits are $0.1 \, cm$ apart, calculate the angular position of the $10^{th}$ bright fringe.
- A$6 \times 10^{-4} \, rad$
- B$6 \times 10^{-3} \, rad$
- C$6 \times 10^{-5} \, rad$
- D$6 \times 10^{-7} \, rad$
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In a Young's double-slit experiment,light of wavelength $5890 \ \mathring A$ is used,and the angular fringe width on the screen is $0.20^\circ$. If the entire apparatus is immersed in water,find the new angular fringe width. (Refractive index of water $\mu = 4/3$) (in $^\circ$)
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View SolutionAssertion : No interference pattern is detected when two coherent sources are infinitely close to each other.
Reason : The fringe width is inversely proportional to the distance between the two slits.
Reason : The fringe width is inversely proportional to the distance between the two slits.
In an interference pattern,if the ratio of slit widths is $1:9$,find the ratio of maximum to minimum intensity.
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View SolutionTwo sources produce an interference pattern which is observed on a screen,at a distance $D$ from the sources. The fringe width is $2w$. If the distance $D$ is now doubled,the fringe width will be:
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View SolutionIf the path difference of the point on the screen from two coherent sources is constant, what is the shape of the trajectory of the point on the screen?
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