$A$ disc of radius $1\,m$ and mass $4\,kg$ rolls on a horizontal plane without slipping in such a way that its centre of mass moves with a speed of $10\,cm/s$. Its rotational kinetic energy is (in $,J$)

  • A
    $0.01$
  • B
    $0.02$
  • C
    $0.03$
  • D
    $0.04$

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Similar Questions

$A$ solid sphere of mass $2 \ kg$ is rolling on a frictionless horizontal surface with velocity $6 \ m \ s^{-1}$. It collides with the free end of an ideal spring whose other end is fixed. The maximum compression produced in the spring will be (Force constant of the spring $= 36 \ N \ m^{-1}$). (in $m$)

$A$ uniform sphere of mass $500\,g$ rolls without slipping on a plane surface such that its centre moves at a speed of $0.02\,m/s$. The total kinetic energy of the rolling sphere would be (in $J$):

$A$ solid sphere of mass $2 \ kg$ and radius $0.5 \ m$ is rolling without slipping on a horizontal surface. The ratio of the rotational and translational kinetic energies of the sphere is (in $: 5$)

$Assertion$: $A$ rigid disc rolls without slipping on a fixed rough horizontal surface with uniform angular velocity. Then the acceleration of the lowest point on the disc is zero.
$Reason$: For a rigid disc rolling without slipping on a fixed rough horizontal surface,the velocity of the lowest point on the disc is always zero.

$A$ sphere of mass $50 \, g$ and diameter $20 \, cm$ is rolling without slipping with a velocity of $5 \, cm/s$. Its total kinetic energy is:

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