A disc is rolling, the velocity of its centre | vedclass

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Question

(D) For a disc rolling without slipping on a horizontal surface, the velocity of any point on the disc is the vector sum of the velocity of the centre

Vedclass · Accepted Answer

the velocity of highest point is $2 v_{cm}$ and point of contact is zero

Vedclass · Answer

(D) For a disc rolling without slipping on a horizontal surface, the velocity of any point on the disc is the vector sum of the velocity of the centre of mass $(v_{cm})$ and the tangential velocity due to rotation $(v_{rot} = R\omega)$.Since the disc is rolling without slipping, the velocity of the point of contact with the ground is zero, which implies $v_{cm} = R\omega$.At the highest point, the velocity is $v_{top} = v_{cm} + R\omega = v_{cm} + v_{cm} = 2v_{cm}$.At the point of contact, the velocity is $v_{contact} = v_{cm} - R\omega = v_{cm} - v_{cm} = 0$.Therefore, the velocity of the highest point is $2v_{cm}$ and the velocity of the point of contact is zero.

$A$ disc is rolling, the velocity of its centre of mass is $v_{cm}$. Which one will be correct?

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