A dilute solution of sulphuric acid is electr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reactions at the electrodes are:At anode: $2H_2O \rightarrow O_2(g) + 4H^+ + 4e^-$At cathode: $4H^+ + 4e^- \rightarrow 2H_2(g)$Total charge pa

Vedclass · Accepted Answer

$127$

Vedclass · Answer

(A) The reactions at the electrodes are:At anode: $2H_2O ightarrow O_2(g) + 4H^+ + 4e^-$At cathode: $4H^+ + 4e^- ightarrow 2H_2(g)$Total charge passed $Q = i 	imes t = 0.10 \ A 	imes 2 	imes 3600 \ s = 720 \ C$.Number of moles of electrons $n_e = \frac{Q}{F} = \frac{720}{96500} \approx 0.00746 \ mol$.From the stoichiometry,$4 \ mol$ of electrons produce $1 \ mol$ of $O_2$ and $2 \ mol$ of $H_2$ (total $3 \ mol$ of gas).Total moles of gas produced $n_{total} = \frac{n_e}{4} + \frac{n_e}{2} = \frac{3}{4} n_e = 0.75 	imes 0.00746 = 0.005595 \ mol$.Volume at $STP = n_{total} 	imes 22.7 \ L \ mol^{-1} = 0.005595 	imes 22.7 \approx 0.127 \ L = 127 \ cm^3$.

Similar Questions

$A$ $200 \ W, 100 \ V$ bulb is connected in series with an electrolytic cell. If an aqueous solution of an $Sn$-salt is electrolysed for $5 \ hrs$,$11.1 \ g$ of $Sn$ gets deposited. The chemical formula of the compound is (Given atomic weight of $Sn$ is $118.7 \ g \ mol^{-1}$).

On passing electric current through molten aluminium chloride,$11.2 \ L$ of $Cl_2$ is liberated at $NTP$ at the anode. The quantity of aluminium deposited at the cathode is .............. $g$ (atomic weight of $Al = 27$).

Faraday's $2^{nd}$ law of electrolysis states that the mass of a substance deposited at an electrode is directly proportional to its:

How many electrons flow when a current of $5 \ A$ is passed through a cell for $200 \ s$?

The atomic weight of $Fe$ is $56$. The weight of $Fe$ deposited from $FeCl_3$ solution by passing $0.6$ Faraday of electricity is $............$ $g$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module