A die has two faces each with number $^{\prime}1^{\prime}$ , three faces each with number $^{\prime}2^{\prime}$ and one face with number $^{\prime}3^{\prime}$. If die is rolled once, determine $P (2)$.

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Total number of faces $=6$

Number of faces with number $^{\prime} 2^{\prime}=3$

$\therefore P(2)=\frac{3}{6}=\frac{1}{2}$

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