(C) The radius of the cylindrical bucket is $r = \frac{28}{2} = 14\, cm$.The height of the bucket is $h = 72\, cm$.The volume of water in the bucket i

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(C) The radius of the cylindrical bucket is $r = \frac{28}{2} = 14\, cm$.The height of the bucket is $h = 72\, cm$.The volume of water in the bucket is given by $V = \pi r^2 h$.$V = \frac{22}{7} \times 14 \times 14 \times 72 = 22 \times 2 \times 14 \times 72 = 44,352\, cm^3$.Let the height of the water level in the rectangular tank be $H$.The volume of water in the tank is $V = \text{length} \times \text{breadth} \times H = 66 \times 28 \times H$.Equating the volumes: $66 \times 28 \times H = 44,352$.$H = \frac{44,352}{66 \times 28} = \frac{44,352}{1,848} = 24\, cm$.

Competitive Quantitative Aptitude Mensuration Measurement of Volume and Surface Area

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$A$ cylindrical bucket is $72\, cm$ high and $28\, cm$ in diameter and is full of water. This water is emptied into a rectangular tank whose length and breadth are $66\, cm$ and $28\, cm$,respectively. What will be the height of the water level in the tank? (in $cm$)

A
$36$
B
$48$
C
$24$
D
$22$

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Measurement of Volume and Surface Area

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$A$ cylindrical bucket is $72\, cm$ high and $28\, cm$ in diameter and is full of water. This water is emptied into a rectangular tank whose length and breadth are $66\, cm$ and $28\, cm$,respectively. What will be the height of the water level in the tank? (in $cm$)

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The circumference of one end of a frustum of a right circular cone is $48\, cm$ and of the other end is $34\, cm$. If the height of the frustum is $10\, cm$,its volume (in $cm^3$) is

The portion of a ditch $48 \ m$ long, $16.5 \ m$ wide, and $4 \ m$ deep that can be filled with stones and earth available during the excavation of a tunnel, cylindrical in shape, of diameter $4 \ m$ and length $56 \ m$ is (Take $\pi = \frac{22}{7}$)

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Consider the volumes of the following:
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$3.$ $A$ cylinder of radius $3\,cm$ and length $3\,cm$.
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The volumes of these in decreasing order are: