A cylinder stands vertically in two immiscibl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The pressure at point $A$ is due to the liquid of density $\rho$ at a depth $h$ from the surface of the upper liquid.$P_A = P_{atm} + \rho gh$The

Vedclass · Accepted Answer

$3\rho gh$

Vedclass · Answer

(B) The pressure at point $A$ is due to the liquid of density $\rho$ at a depth $h$ from the surface of the upper liquid.$P_A = P_{atm} + \rho gh$The pressure at point $B$ is due to the liquid of density $\rho$ (height $2h$) and the liquid of density $2\rho$ (height $h$).$P_B = P_{atm} + \rho g(2h) + (2\rho)gh = P_{atm} + 2\rho gh + 2\rho gh = P_{atm} + 4\rho gh$The difference in pressure between point $B$ and point $A$ is:$P_B - P_A = (P_{atm} + 4\rho gh) - (P_{atm} + \rho gh) = 3\rho gh$

$A$ cylinder stands vertically in two immiscible liquids of densities $\rho$ and $2\rho$. The heights of the two liquids are shown in the figure. Find the difference in pressure at point $A$ and point $B$.

Similar Questions

If two liquids of same volume but different densities $\rho_1$ and $\rho_2$ are mixed,then the density of the mixture is given by:

$A$ beaker containing a liquid is kept inside a big closed jar. If the air inside the jar is continuously pumped out,the pressure in the liquid near the bottom of the liquid will

Is pressure a scalar or a vector quantity? Explain.

The densities of ice and water are $\rho$ and $\sigma$ respectively. What is the change in volume when a mass $M$ of ice melts?

The volume of an air bubble is doubled as it rises from the bottom of a lake to its surface. The atmospheric pressure is $75 \, cm$ of mercury. The ratio of the density of mercury to that of lake water is $\frac{40}{3}$. The depth of the lake in metres is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module