A cylinder of radius R made of a material of | vedclass

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Question

Let $R_{1}$ and $R_{2}$ be the thermal resistances of inner and outer potions. since, temperature difference at both ends is same, the resistances are

Vedclass · Accepted Answer

$\frac{1}{4}(k_1+3k_2)$

Vedclass · Answer

Let $R_{1}$ and $R_{2}$ be the thermal resistances of inner and outer potions. since, temperature difference at both ends is same, the resistances are in parallel.

Hence,

$\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}$

$R=\frac{l}{K A}$

or $\frac{1}{R}=\frac{K A}{l}$

$	herefore\left(\frac{K\left(4 \pi R^{2}ight)}{l}ight)=\frac{K_{1}\left(\pi R^{2}ight)}{l}+\frac{K_{2}\left(3 \pi R^{2}ight)}{l}$

$	herefore K=\frac{K_{1}+3 K_{2}}{4}$

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