A cyclist starts from the point P of a circul | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The cyclist moves along the circumference from point $P$ to point $S$. Since the path is circular, the points $P, O, S$ form a right-angled triang

Vedclass · Accepted Answer

$\sqrt{8} \,km$

Vedclass · Answer

(B) The cyclist moves along the circumference from point $P$ to point $S$. Since the path is circular, the points $P, O, S$ form a right-angled triangle where $O$ is the center of the circle. The displacement is the straight-line distance between the initial point $P$ and the final point $S$. Using the Pythagorean theorem in $	riangle POS$, the displacement $d$ is given by: $d = \sqrt{OP^2 + OS^2}$ Given the radius $R = 2 \,km$, we have $OP = OS = R = 2 \,km$. $d = \sqrt{R^2 + R^2} = \sqrt{2R^2} = R\sqrt{2}$ Substituting the value of $R$: $d = 2\sqrt{2} \,km = \sqrt{4 	imes 2} \,km = \sqrt{8} \,km$.

$A$ cyclist starts from the point $P$ of a circular ground of radius $2 \,km$ and travels along its circumference to the point $S$. The displacement of a cyclist is:

Similar Questions

Explain path length.

$A$ particle moves along the circumference of a circle of radius $r$ from point $A$ to point $B$ as shown in the figure. What are the path length and displacement?

The position vector of a particle is given by the expression $\vec{r} = 3t^2 \hat{i} + 4t^2 \hat{j} + 7 \hat{k}$. The distance traversed in the first $10 \, s$ is ......... $m$.

Explain with an example that the magnitude of displacement may be zero but the corresponding path length is not zero.

What is motion? Mention different types of motions.

Vedclass Test Series

Exam Paper Generator

Online Exam Module