A cyclist goes once around a circular track of diameter $105$ metre in $5$ minutes. Calculate his speed.
A cyclist goes once around a circular track of diameter $105$ metre in $5$ minutes. Calculate his speed.
Given $D=105 m , R =\frac{105}{2}=52.5 m$
$t=5 \times 60=300 s$
Now, speed $=\frac{\text { distance }}{\text { time }}=\frac{2 \times 3.14 \times 52.5}{300}$
$=1.1 m s ^{-1}$
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$(i)$ How much ahead of $A$ is $B$ when the motion starts ?
$(ii)$ What is the speed of $B$ ?
$(iii)$ When and where $A$ will catch $B$ ?
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$(v)$ Is the speed of either trains uniform or non uniform ? Justify your answer.
The distance$-$time graph of two trains are given below. The trains start simultaneously in the same direction.
$(i)$ How much ahead of $A$ is $B$ when the motion starts ?
$(ii)$ What is the speed of $B$ ?
$(iii)$ When and where $A$ will catch $B$ ?
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$10$
$20$
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$0$
$2$
$4$
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$8$
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Displacement $(m)$
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$2$
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