A current of 2.0 , A passes through a cell of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The potential difference $V$ across the terminals of a cell discharging current $i$ is given by the formula: $V = E - ir$.Here,$E = 1.5 \, V$ is t

Vedclass · Accepted Answer

$1.2$

Vedclass · Answer

(D) The potential difference $V$ across the terminals of a cell discharging current $i$ is given by the formula: $V = E - ir$.Here,$E = 1.5 \, V$ is the electromotive force,$i = 2.0 \, A$ is the current,and $r = 0.15 \, \Omega$ is the internal resistance.Substituting the values into the equation:$V = 1.5 - (2.0 	imes 0.15)$$V = 1.5 - 0.30$$V = 1.2 \, V$.Therefore,the potential difference across the ends of the cell is $1.2 \, V$.

$A$ current of $2.0 \, A$ passes through a cell of $e.m.f.$ $1.5 \, V$ having an internal resistance of $0.15 \, \Omega$. The potential difference measured,in $volts$,across the terminals of the cell will be:

Similar Questions

The reading of the ammeter as shown in the figure is:

The resistance between the terminal points $A$ and $B$ of the given infinitely long circuit will be

If the ammeter in the given circuit reads $2\, A$,the resistance $R$ is ............ $\Omega$.

If the power dissipated in the $3\,\Omega$ resistor is $27\,W$,then what is the power dissipated in the $2\,\Omega$ resistor (in $,W$)?

For the given circuit diagram,if the dissipated electrical power is $150 \text{ W}$,find the value of resistance $R$. (in $Omega$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module