A current of 3 , A is flowing in a plane circ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic dipole moment $M$ of a current-carrying coil is given by the formula:$M = N \cdot I \cdot A$Where:$N = 20$ (number of turns)$I = 3 \,

Vedclass · Accepted Answer

$0.3$

Vedclass · Answer

(B) The magnetic dipole moment $M$ of a current-carrying coil is given by the formula:$M = N \cdot I \cdot A$Where:$N = 20$ (number of turns)$I = 3 \, A$ (current)$A = \pi \cdot r^2$ (area of the coil)Given radius $r = 4 \, cm = 0.04 \, m$.Substituting the values:$A = \pi \cdot (0.04)^2 = \pi \cdot 0.0016 \, m^2$$M = 20 	imes 3 	imes \pi 	imes 0.0016$$M = 60 	imes 0.0050265$$M \approx 0.3016 \, A \cdot m^2$Rounding to the nearest provided option,the value is $0.3 \, A \cdot m^2$.

$A$ current of $3 \, A$ is flowing in a plane circular coil of radius $4 \, cm$ and number of turns $20$. The coil is placed in a uniform magnetic field of magnetic induction $0.5 \, T$. The magnetic dipole moment of the coil is $... \, A \cdot m^2$.

Similar Questions

An insulating rod of length $l$ carries a charge $q$ distributed uniformly on it. The rod is pivoted at an end and is rotated at a frequency $f$ about a fixed perpendicular axis. The magnetic moment of the system is

Two wires of the same length are shaped into a square and a circle. If they carry the same current,the ratio of their magnetic moments is:

$A$ circular coil of area $2 \,cm^2$ has $1000$ turns. If the current through the coil is $1 \,A$, then its magnetic moment is (in $\,Am^2$)

$A$ rod of length $l$ having uniformly distributed charge $Q$ is rotated about one end with constant frequency $f$. Its magnetic moment is:

Write the equation of the magnetic dipole moment in terms of electric current.

Vedclass Test Series

Exam Paper Generator

Online Exam Module