A current of 10.0 , A flows for 2.00 , h thro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total charge $Q$ passed through the cell is given by $Q = i 	imes t$.Given $i = 10.0 \, A$ and $t = 2.00 \, h = 2.00 	imes 3600 \, s = 7200

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) The total charge $Q$ passed through the cell is given by $Q = i 	imes t$.Given $i = 10.0 \, A$ and $t = 2.00 \, h = 2.00 	imes 3600 \, s = 7200 \, s$.$Q = 10.0 \, A 	imes 7200 \, s = 72,000 \, C$.According to Faraday's law,the number of moles of electrons required to deposit $n$ moles of metal $X$ with oxidation state $x$ is $n 	imes x = \frac{Q}{F}$.Here,$n = 0.250 \, mol$ and $F = 96,500 \, C \, mol^{-1}$.$0.250 	imes x = \frac{72,000}{96,500}$.$0.250 	imes x \approx 0.746$.$x = \frac{0.746}{0.250} \approx 2.98 \approx 3$.Therefore,the oxidation state of metal $X$ is $3+$.

Column $I$ (Reduction process)	Column $II$ (Charge required)
$(a)$ $1$ mol of $MnO_4^-$ to $Mn^{2+}$	$(p)$ $193000$ $C$
$(b)$ $1$ mole of $Cr_2O_7^{2-}$ to $Cr^{3+}$	$(q)$ $289500$ $C$
$(c)$ $1$ mole of $Sn^{4+}$ to $Sn^{2+}$	$(r)$ $482500$ $C$
$(d)$ $1$ mole of $Al^{3+}$ to $Al$	$(s)$ $579000$ $C$

$A$ current of $10.0 \, A$ flows for $2.00 \, h$ through an electrolytic cell containing a molten salt of metal $X$. This results in the decomposition of $0.250 \, mol$ of metal $X$ at the cathode. The oxidation state of $X$ in the molten salt is $(F = 96,500 \, C \, mol^{-1})$ (in $+$)

Similar Questions

Faraday has the dimensions of

In the electrolysis of $AgNO_3$,the mass of $Ag$ deposited is plotted against the charge. Slope of the line gives

The electrochemical equivalent of a metal is $x \ g \ C^{-1}$. The equivalent weight of the metal is:

If nearly $10^5 \ C$ liberate $1 \ gm$ equivalent of aluminium,then the amount of aluminium (equivalent weight $9$) deposited through electrolysis in $20 \ minutes$ by a current of $50 \ A$ will be .............. $gm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module