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(C) For a floating body,the weight of the block is equal to the total buoyant force exerted by the displaced fluids.Weight of block = Weight of displa

Vedclass · Accepted Answer

$760$

Vedclass · Answer

(C) For a floating body,the weight of the block is equal to the total buoyant force exerted by the displaced fluids.Weight of block = Weight of displaced oil + Weight of displaced water$mg = V_{oil} \cdot ho_{oil} \cdot g + V_{water} \cdot ho_{water} \cdot g$Since the block is a cube of side $10 \, cm$,the total height is $10 \, cm$. If $4 \, cm$ is in water,then $6 \, cm$ is in oil.$V_{oil} = 10 	imes 10 	imes 6 = 600 \, cm^3$$V_{water} = 10 	imes 10 	imes 4 = 400 \, cm^3$$m = (600 	imes 0.6) + (400 	imes 1)$$m = 360 + 400 = 760 \, gm$.

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