A cord is used to lower vertically a block of | vedclass

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(C) When the block moves vertically downward with acceleration $a = \frac{g}{4}$,the forces acting on the block are the gravitational force $Mg$ (down

Vedclass · Accepted Answer

$-\frac{3}{4}Mgd$

Vedclass · Answer

(C) When the block moves vertically downward with acceleration $a = \frac{g}{4}$,the forces acting on the block are the gravitational force $Mg$ (downward) and the tension $T$ in the cord (upward).Using Newton's second law for the downward direction: $Mg - T = Ma$.Substituting $a = \frac{g}{4}$,we get $Mg - T = M(\frac{g}{4})$.Therefore,the tension in the cord is $T = Mg - \frac{Mg}{4} = \frac{3}{4}Mg$.The work done by the cord on the block is given by $W = \vec{T} \cdot \vec{d} = Td \cos(180^\circ)$ because the tension acts upward while the displacement is downward.$W = (\frac{3}{4}Mg) 	imes d 	imes (-1) = -\frac{3}{4}Mgd$.

$A$ cord is used to lower vertically a block of mass $M$ by a distance $d$ with constant downward acceleration $\frac{g}{4}$. Work done by the cord on the block is

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