A convex mirror of focal length f forms an im | vedclass

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(A) For a convex mirror,the magnification $m$ is given by $m = +\frac{1}{n}$.Using the magnification formula $m = -\frac{v}{u}$,we have $\frac{1}{n} =

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$(n - 1)f$

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(A) For a convex mirror,the magnification $m$ is given by $m = +\frac{1}{n}$.Using the magnification formula $m = -\frac{v}{u}$,we have $\frac{1}{n} = -\frac{v}{u}$,which implies $v = -\frac{u}{n}$.According to the mirror formula,$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$.Substituting the value of $v$,we get $\frac{1}{f} = \frac{1}{-u/n} + \frac{1}{u} = -\frac{n}{u} + \frac{1}{u} = \frac{1 - n}{u}$.Therefore,$u = f(1 - n) = -(n - 1)f$.The distance of the object from the mirror is the magnitude of $u$,which is $(n - 1)f$.

Element	$M^{3+}/M$	$M^{+}/M$
$Al$	$-1.66$	$+0.55$
$Tl$	$+1.26$	$-0.34$

$A$ convex mirror of focal length $f$ forms an image which is $1/n$ times the object. The distance of the object from the mirror is

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Element $M^{3+}/M$ $M^{+}/M$

$Al$ $-1.66$ $+0.55$

$Tl$ $+1.26$ $-0.34$

Based on these data,which of the following statements is correct?

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