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(B) For the displacement method of a convex lens,if the object and screen are fixed at a distance $D$,there are two positions of the lens where a real

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$6$

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(B) For the displacement method of a convex lens,if the object and screen are fixed at a distance $D$,there are two positions of the lens where a real image is formed on the screen.Let the height of the object be $O$ and the heights of the two images be $I_1$ and $I_2$.The relationship between the object height and the image heights is given by the formula: $O = \sqrt{I_1 	imes I_2}$.Given $I_1 = 4 \ cm$ and $I_2 = 9 \ cm$.Substituting these values into the formula:$O = \sqrt{4 	imes 9}$$O = \sqrt{36}$$O = 6 \ cm$.Therefore,the height of the object is $6 \ cm$.

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